Y=25-3x+2x^2

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Solution for Y=25-3x+2x^2 equation: 



=25-3Y+2Y^2

We move all terms to the left:

-(25-3Y+2Y^2)=0

We get rid of parentheses

-2Y^2+3Y-25=0

a = -2; b = 3; c = -25;
Δ = b2-4ac
Δ = 32-4·(-2)·(-25)
Δ = -191
Delta is less than zero, so there is no solution for the equation

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